Optimal. Leaf size=125 \[ -\frac {\left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2}{8 c^4}+\frac {a b x^2}{4 c^3}+\frac {1}{8} x^8 \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2+\frac {b x^6 \left (a+b \tanh ^{-1}\left (c x^2\right )\right )}{12 c}+\frac {b^2 x^2 \tanh ^{-1}\left (c x^2\right )}{4 c^3}+\frac {b^2 x^4}{24 c^2}+\frac {b^2 \log \left (1-c^2 x^4\right )}{6 c^4} \]
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Rubi [C] time = 1.55, antiderivative size = 636, normalized size of antiderivative = 5.09, number of steps used = 62, number of rules used = 19, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.187, Rules used = {6099, 2454, 2398, 2411, 43, 2334, 12, 14, 2301, 2395, 2439, 2416, 2389, 2295, 2394, 2393, 2391, 2410, 2390} \[ \frac {b^2 \text {PolyLog}\left (2,\frac {1}{2} \left (1-c x^2\right )\right )}{16 c^4}+\frac {b^2 \text {PolyLog}\left (2,\frac {1}{2} \left (c x^2+1\right )\right )}{16 c^4}+\frac {a b x^2}{8 c^3}-\frac {b x^4 \left (2 a-b \log \left (1-c x^2\right )\right )}{32 c^2}-\frac {1}{192} b \left (-\frac {3 \left (1-c x^2\right )^4}{c^4}+\frac {16 \left (1-c x^2\right )^3}{c^4}-\frac {36 \left (1-c x^2\right )^2}{c^4}+\frac {48 \left (1-c x^2\right )}{c^4}-\frac {12 \log \left (1-c x^2\right )}{c^4}\right ) \left (2 a-b \log \left (1-c x^2\right )\right )-\frac {b \log \left (\frac {1}{2} \left (c x^2+1\right )\right ) \left (2 a-b \log \left (1-c x^2\right )\right )}{16 c^4}+\frac {1}{32} x^8 \left (2 a-b \log \left (1-c x^2\right )\right )^2-\frac {1}{64} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right )+\frac {1}{16} b x^8 \log \left (c x^2+1\right ) \left (2 a-b \log \left (1-c x^2\right )\right )+\frac {b x^6 \left (2 a-b \log \left (1-c x^2\right )\right )}{48 c}+\frac {b^2 x^4}{128 c^2}+\frac {23 b^2 x^2}{192 c^3}+\frac {b^2 \left (1-c x^2\right )^4}{256 c^4}-\frac {b^2 \left (1-c x^2\right )^3}{36 c^4}+\frac {3 b^2 \left (1-c x^2\right )^2}{32 c^4}+\frac {b^2 \log ^2\left (1-c x^2\right )}{32 c^4}-\frac {b^2 \log ^2\left (c x^2+1\right )}{32 c^4}+\frac {b^2 \left (1-c x^2\right ) \log \left (1-c x^2\right )}{16 c^4}-\frac {5 b^2 \log \left (1-c x^2\right )}{192 c^4}+\frac {b^2 \left (c x^2+1\right ) \log \left (c x^2+1\right )}{8 c^4}+\frac {b^2 \log \left (\frac {1}{2} \left (1-c x^2\right )\right ) \log \left (c x^2+1\right )}{16 c^4}+\frac {b^2 \log \left (c x^2+1\right )}{24 c^4}-\frac {7 b^2 x^6}{576 c}+\frac {1}{32} b^2 x^8 \log ^2\left (c x^2+1\right )+\frac {b^2 x^6 \log \left (c x^2+1\right )}{24 c}-\frac {1}{256} b^2 x^8 \]
Warning: Unable to verify antiderivative.
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Rule 12
Rule 14
Rule 43
Rule 2295
Rule 2301
Rule 2334
Rule 2389
Rule 2390
Rule 2391
Rule 2393
Rule 2394
Rule 2395
Rule 2398
Rule 2410
Rule 2411
Rule 2416
Rule 2439
Rule 2454
Rule 6099
Rubi steps
\begin {align*} \int x^7 \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \, dx &=\int \left (\frac {1}{4} x^7 \left (2 a-b \log \left (1-c x^2\right )\right )^2-\frac {1}{2} b x^7 \left (-2 a+b \log \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )+\frac {1}{4} b^2 x^7 \log ^2\left (1+c x^2\right )\right ) \, dx\\ &=\frac {1}{4} \int x^7 \left (2 a-b \log \left (1-c x^2\right )\right )^2 \, dx-\frac {1}{2} b \int x^7 \left (-2 a+b \log \left (1-c x^2\right )\right ) \log \left (1+c x^2\right ) \, dx+\frac {1}{4} b^2 \int x^7 \log ^2\left (1+c x^2\right ) \, dx\\ &=\frac {1}{8} \operatorname {Subst}\left (\int x^3 (2 a-b \log (1-c x))^2 \, dx,x,x^2\right )-\frac {1}{4} b \operatorname {Subst}\left (\int x^3 (-2 a+b \log (1-c x)) \log (1+c x) \, dx,x,x^2\right )+\frac {1}{8} b^2 \operatorname {Subst}\left (\int x^3 \log ^2(1+c x) \, dx,x,x^2\right )\\ &=\frac {1}{32} x^8 \left (2 a-b \log \left (1-c x^2\right )\right )^2+\frac {1}{16} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )+\frac {1}{32} b^2 x^8 \log ^2\left (1+c x^2\right )-\frac {1}{16} (b c) \operatorname {Subst}\left (\int \frac {x^4 (2 a-b \log (1-c x))}{1-c x} \, dx,x,x^2\right )+\frac {1}{16} (b c) \operatorname {Subst}\left (\int \frac {x^4 (-2 a+b \log (1-c x))}{1+c x} \, dx,x,x^2\right )-\frac {1}{16} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {x^4 \log (1+c x)}{1-c x} \, dx,x,x^2\right )-\frac {1}{16} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {x^4 \log (1+c x)}{1+c x} \, dx,x,x^2\right )\\ &=\frac {1}{32} x^8 \left (2 a-b \log \left (1-c x^2\right )\right )^2+\frac {1}{16} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )+\frac {1}{32} b^2 x^8 \log ^2\left (1+c x^2\right )+\frac {1}{16} b \operatorname {Subst}\left (\int \frac {\left (\frac {1}{c}-\frac {x}{c}\right )^4 (2 a-b \log (x))}{x} \, dx,x,1-c x^2\right )+\frac {1}{16} (b c) \operatorname {Subst}\left (\int \left (-\frac {-2 a+b \log (1-c x)}{c^4}+\frac {x (-2 a+b \log (1-c x))}{c^3}-\frac {x^2 (-2 a+b \log (1-c x))}{c^2}+\frac {x^3 (-2 a+b \log (1-c x))}{c}+\frac {-2 a+b \log (1-c x)}{c^4 (1+c x)}\right ) \, dx,x,x^2\right )-\frac {1}{16} \left (b^2 c\right ) \operatorname {Subst}\left (\int \left (-\frac {\log (1+c x)}{c^4}-\frac {x \log (1+c x)}{c^3}-\frac {x^2 \log (1+c x)}{c^2}-\frac {x^3 \log (1+c x)}{c}-\frac {\log (1+c x)}{c^4 (-1+c x)}\right ) \, dx,x,x^2\right )-\frac {1}{16} \left (b^2 c\right ) \operatorname {Subst}\left (\int \left (-\frac {\log (1+c x)}{c^4}+\frac {x \log (1+c x)}{c^3}-\frac {x^2 \log (1+c x)}{c^2}+\frac {x^3 \log (1+c x)}{c}+\frac {\log (1+c x)}{c^4 (1+c x)}\right ) \, dx,x,x^2\right )\\ &=\frac {1}{32} x^8 \left (2 a-b \log \left (1-c x^2\right )\right )^2-\frac {1}{192} b \left (2 a-b \log \left (1-c x^2\right )\right ) \left (\frac {48 \left (1-c x^2\right )}{c^4}-\frac {36 \left (1-c x^2\right )^2}{c^4}+\frac {16 \left (1-c x^2\right )^3}{c^4}-\frac {3 \left (1-c x^2\right )^4}{c^4}-\frac {12 \log \left (1-c x^2\right )}{c^4}\right )+\frac {1}{16} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )+\frac {1}{32} b^2 x^8 \log ^2\left (1+c x^2\right )+\frac {1}{16} b \operatorname {Subst}\left (\int x^3 (-2 a+b \log (1-c x)) \, dx,x,x^2\right )+\frac {1}{16} b^2 \operatorname {Subst}\left (\int \frac {x \left (-48+36 x-16 x^2+3 x^3\right )+12 \log (x)}{12 c^4 x} \, dx,x,1-c x^2\right )-\frac {b \operatorname {Subst}\left (\int (-2 a+b \log (1-c x)) \, dx,x,x^2\right )}{16 c^3}+\frac {b \operatorname {Subst}\left (\int \frac {-2 a+b \log (1-c x)}{1+c x} \, dx,x,x^2\right )}{16 c^3}+2 \frac {b^2 \operatorname {Subst}\left (\int \log (1+c x) \, dx,x,x^2\right )}{16 c^3}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\log (1+c x)}{-1+c x} \, dx,x,x^2\right )}{16 c^3}-\frac {b^2 \operatorname {Subst}\left (\int \frac {\log (1+c x)}{1+c x} \, dx,x,x^2\right )}{16 c^3}+\frac {b \operatorname {Subst}\left (\int x (-2 a+b \log (1-c x)) \, dx,x,x^2\right )}{16 c^2}-\frac {b \operatorname {Subst}\left (\int x^2 (-2 a+b \log (1-c x)) \, dx,x,x^2\right )}{16 c}+2 \frac {b^2 \operatorname {Subst}\left (\int x^2 \log (1+c x) \, dx,x,x^2\right )}{16 c}\\ &=\frac {a b x^2}{8 c^3}-\frac {b x^4 \left (2 a-b \log \left (1-c x^2\right )\right )}{32 c^2}+\frac {b x^6 \left (2 a-b \log \left (1-c x^2\right )\right )}{48 c}-\frac {1}{64} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right )+\frac {1}{32} x^8 \left (2 a-b \log \left (1-c x^2\right )\right )^2-\frac {1}{192} b \left (2 a-b \log \left (1-c x^2\right )\right ) \left (\frac {48 \left (1-c x^2\right )}{c^4}-\frac {36 \left (1-c x^2\right )^2}{c^4}+\frac {16 \left (1-c x^2\right )^3}{c^4}-\frac {3 \left (1-c x^2\right )^4}{c^4}-\frac {12 \log \left (1-c x^2\right )}{c^4}\right )-\frac {b \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (\frac {1}{2} \left (1+c x^2\right )\right )}{16 c^4}+\frac {b^2 \log \left (\frac {1}{2} \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )}{16 c^4}+\frac {1}{16} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )+\frac {1}{32} b^2 x^8 \log ^2\left (1+c x^2\right )-\frac {1}{48} b^2 \operatorname {Subst}\left (\int \frac {x^3}{1-c x} \, dx,x,x^2\right )+2 \left (\frac {b^2 x^6 \log \left (1+c x^2\right )}{48 c}-\frac {1}{48} b^2 \operatorname {Subst}\left (\int \frac {x^3}{1+c x} \, dx,x,x^2\right )\right )+\frac {b^2 \operatorname {Subst}\left (\int \frac {x \left (-48+36 x-16 x^2+3 x^3\right )+12 \log (x)}{x} \, dx,x,1-c x^2\right )}{192 c^4}+2 \frac {b^2 \operatorname {Subst}\left (\int \log (x) \, dx,x,1+c x^2\right )}{16 c^4}-\frac {b^2 \operatorname {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,1+c x^2\right )}{16 c^4}-\frac {b^2 \operatorname {Subst}\left (\int \frac {\log \left (\frac {1}{2} (1-c x)\right )}{1+c x} \, dx,x,x^2\right )}{16 c^3}-\frac {b^2 \operatorname {Subst}\left (\int \log (1-c x) \, dx,x,x^2\right )}{16 c^3}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\log \left (\frac {1}{2} (1+c x)\right )}{1-c x} \, dx,x,x^2\right )}{16 c^3}+\frac {b^2 \operatorname {Subst}\left (\int \frac {x^2}{1-c x} \, dx,x,x^2\right )}{32 c}+\frac {1}{64} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {x^4}{1-c x} \, dx,x,x^2\right )\\ &=\frac {a b x^2}{8 c^3}-\frac {b x^4 \left (2 a-b \log \left (1-c x^2\right )\right )}{32 c^2}+\frac {b x^6 \left (2 a-b \log \left (1-c x^2\right )\right )}{48 c}-\frac {1}{64} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right )+\frac {1}{32} x^8 \left (2 a-b \log \left (1-c x^2\right )\right )^2-\frac {1}{192} b \left (2 a-b \log \left (1-c x^2\right )\right ) \left (\frac {48 \left (1-c x^2\right )}{c^4}-\frac {36 \left (1-c x^2\right )^2}{c^4}+\frac {16 \left (1-c x^2\right )^3}{c^4}-\frac {3 \left (1-c x^2\right )^4}{c^4}-\frac {12 \log \left (1-c x^2\right )}{c^4}\right )-\frac {b \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (\frac {1}{2} \left (1+c x^2\right )\right )}{16 c^4}+\frac {b^2 \log \left (\frac {1}{2} \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )}{16 c^4}+\frac {1}{16} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )-\frac {b^2 \log ^2\left (1+c x^2\right )}{32 c^4}+\frac {1}{32} b^2 x^8 \log ^2\left (1+c x^2\right )+2 \left (-\frac {b^2 x^2}{16 c^3}+\frac {b^2 \left (1+c x^2\right ) \log \left (1+c x^2\right )}{16 c^4}\right )-\frac {1}{48} b^2 \operatorname {Subst}\left (\int \left (-\frac {1}{c^3}-\frac {x}{c^2}-\frac {x^2}{c}-\frac {1}{c^3 (-1+c x)}\right ) \, dx,x,x^2\right )+2 \left (\frac {b^2 x^6 \log \left (1+c x^2\right )}{48 c}-\frac {1}{48} b^2 \operatorname {Subst}\left (\int \left (\frac {1}{c^3}-\frac {x}{c^2}+\frac {x^2}{c}-\frac {1}{c^3 (1+c x)}\right ) \, dx,x,x^2\right )\right )+\frac {b^2 \operatorname {Subst}\left (\int \left (-48+36 x-16 x^2+3 x^3+\frac {12 \log (x)}{x}\right ) \, dx,x,1-c x^2\right )}{192 c^4}-\frac {b^2 \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right )}{x} \, dx,x,1-c x^2\right )}{16 c^4}-\frac {b^2 \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right )}{x} \, dx,x,1+c x^2\right )}{16 c^4}+\frac {b^2 \operatorname {Subst}\left (\int \log (x) \, dx,x,1-c x^2\right )}{16 c^4}+\frac {b^2 \operatorname {Subst}\left (\int \left (-\frac {1}{c^2}-\frac {x}{c}-\frac {1}{c^2 (-1+c x)}\right ) \, dx,x,x^2\right )}{32 c}+\frac {1}{64} \left (b^2 c\right ) \operatorname {Subst}\left (\int \left (-\frac {1}{c^4}-\frac {x}{c^3}-\frac {x^2}{c^2}-\frac {x^3}{c}-\frac {1}{c^4 (-1+c x)}\right ) \, dx,x,x^2\right )\\ &=\frac {a b x^2}{8 c^3}+\frac {55 b^2 x^2}{192 c^3}-\frac {5 b^2 x^4}{384 c^2}+\frac {b^2 x^6}{576 c}-\frac {b^2 x^8}{256}+\frac {3 b^2 \left (1-c x^2\right )^2}{32 c^4}-\frac {b^2 \left (1-c x^2\right )^3}{36 c^4}+\frac {b^2 \left (1-c x^2\right )^4}{256 c^4}-\frac {5 b^2 \log \left (1-c x^2\right )}{192 c^4}+\frac {b^2 \left (1-c x^2\right ) \log \left (1-c x^2\right )}{16 c^4}-\frac {b x^4 \left (2 a-b \log \left (1-c x^2\right )\right )}{32 c^2}+\frac {b x^6 \left (2 a-b \log \left (1-c x^2\right )\right )}{48 c}-\frac {1}{64} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right )+\frac {1}{32} x^8 \left (2 a-b \log \left (1-c x^2\right )\right )^2-\frac {1}{192} b \left (2 a-b \log \left (1-c x^2\right )\right ) \left (\frac {48 \left (1-c x^2\right )}{c^4}-\frac {36 \left (1-c x^2\right )^2}{c^4}+\frac {16 \left (1-c x^2\right )^3}{c^4}-\frac {3 \left (1-c x^2\right )^4}{c^4}-\frac {12 \log \left (1-c x^2\right )}{c^4}\right )-\frac {b \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (\frac {1}{2} \left (1+c x^2\right )\right )}{16 c^4}+\frac {b^2 \log \left (\frac {1}{2} \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )}{16 c^4}+\frac {1}{16} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )-\frac {b^2 \log ^2\left (1+c x^2\right )}{32 c^4}+\frac {1}{32} b^2 x^8 \log ^2\left (1+c x^2\right )+2 \left (-\frac {b^2 x^2}{48 c^3}+\frac {b^2 x^4}{96 c^2}-\frac {b^2 x^6}{144 c}+\frac {b^2 \log \left (1+c x^2\right )}{48 c^4}+\frac {b^2 x^6 \log \left (1+c x^2\right )}{48 c}\right )+2 \left (-\frac {b^2 x^2}{16 c^3}+\frac {b^2 \left (1+c x^2\right ) \log \left (1+c x^2\right )}{16 c^4}\right )+\frac {b^2 \text {Li}_2\left (\frac {1}{2} \left (1-c x^2\right )\right )}{16 c^4}+\frac {b^2 \text {Li}_2\left (\frac {1}{2} \left (1+c x^2\right )\right )}{16 c^4}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,1-c x^2\right )}{16 c^4}\\ &=\frac {a b x^2}{8 c^3}+\frac {55 b^2 x^2}{192 c^3}-\frac {5 b^2 x^4}{384 c^2}+\frac {b^2 x^6}{576 c}-\frac {b^2 x^8}{256}+\frac {3 b^2 \left (1-c x^2\right )^2}{32 c^4}-\frac {b^2 \left (1-c x^2\right )^3}{36 c^4}+\frac {b^2 \left (1-c x^2\right )^4}{256 c^4}-\frac {5 b^2 \log \left (1-c x^2\right )}{192 c^4}+\frac {b^2 \left (1-c x^2\right ) \log \left (1-c x^2\right )}{16 c^4}+\frac {b^2 \log ^2\left (1-c x^2\right )}{32 c^4}-\frac {b x^4 \left (2 a-b \log \left (1-c x^2\right )\right )}{32 c^2}+\frac {b x^6 \left (2 a-b \log \left (1-c x^2\right )\right )}{48 c}-\frac {1}{64} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right )+\frac {1}{32} x^8 \left (2 a-b \log \left (1-c x^2\right )\right )^2-\frac {1}{192} b \left (2 a-b \log \left (1-c x^2\right )\right ) \left (\frac {48 \left (1-c x^2\right )}{c^4}-\frac {36 \left (1-c x^2\right )^2}{c^4}+\frac {16 \left (1-c x^2\right )^3}{c^4}-\frac {3 \left (1-c x^2\right )^4}{c^4}-\frac {12 \log \left (1-c x^2\right )}{c^4}\right )-\frac {b \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (\frac {1}{2} \left (1+c x^2\right )\right )}{16 c^4}+\frac {b^2 \log \left (\frac {1}{2} \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )}{16 c^4}+\frac {1}{16} b x^8 \left (2 a-b \log \left (1-c x^2\right )\right ) \log \left (1+c x^2\right )-\frac {b^2 \log ^2\left (1+c x^2\right )}{32 c^4}+\frac {1}{32} b^2 x^8 \log ^2\left (1+c x^2\right )+2 \left (-\frac {b^2 x^2}{48 c^3}+\frac {b^2 x^4}{96 c^2}-\frac {b^2 x^6}{144 c}+\frac {b^2 \log \left (1+c x^2\right )}{48 c^4}+\frac {b^2 x^6 \log \left (1+c x^2\right )}{48 c}\right )+2 \left (-\frac {b^2 x^2}{16 c^3}+\frac {b^2 \left (1+c x^2\right ) \log \left (1+c x^2\right )}{16 c^4}\right )+\frac {b^2 \text {Li}_2\left (\frac {1}{2} \left (1-c x^2\right )\right )}{16 c^4}+\frac {b^2 \text {Li}_2\left (\frac {1}{2} \left (1+c x^2\right )\right )}{16 c^4}\\ \end {align*}
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Mathematica [A] time = 0.08, size = 146, normalized size = 1.17 \[ \frac {3 a^2 c^4 x^8+2 a b c^3 x^6+2 b c x^2 \tanh ^{-1}\left (c x^2\right ) \left (3 a c^3 x^6+b \left (c^2 x^4+3\right )\right )+6 a b c x^2+b (3 a+4 b) \log \left (1-c x^2\right )-3 a b \log \left (c x^2+1\right )+3 b^2 \left (c^4 x^8-1\right ) \tanh ^{-1}\left (c x^2\right )^2+b^2 c^2 x^4+4 b^2 \log \left (c x^2+1\right )}{24 c^4} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.86, size = 176, normalized size = 1.41 \[ \frac {12 \, a^{2} c^{4} x^{8} + 8 \, a b c^{3} x^{6} + 4 \, b^{2} c^{2} x^{4} + 24 \, a b c x^{2} + 3 \, {\left (b^{2} c^{4} x^{8} - b^{2}\right )} \log \left (-\frac {c x^{2} + 1}{c x^{2} - 1}\right )^{2} - 4 \, {\left (3 \, a b - 4 \, b^{2}\right )} \log \left (c x^{2} + 1\right ) + 4 \, {\left (3 \, a b + 4 \, b^{2}\right )} \log \left (c x^{2} - 1\right ) + 4 \, {\left (3 \, a b c^{4} x^{8} + b^{2} c^{3} x^{6} + 3 \, b^{2} c x^{2}\right )} \log \left (-\frac {c x^{2} + 1}{c x^{2} - 1}\right )}{96 \, c^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.28, size = 175, normalized size = 1.40 \[ \frac {1}{8} \, a^{2} x^{8} + \frac {a b x^{6}}{12 \, c} + \frac {b^{2} x^{4}}{24 \, c^{2}} + \frac {1}{32} \, {\left (b^{2} x^{8} - \frac {b^{2}}{c^{4}}\right )} \log \left (-\frac {c x^{2} + 1}{c x^{2} - 1}\right )^{2} + \frac {1}{24} \, {\left (3 \, a b x^{8} + \frac {b^{2} x^{6}}{c} + \frac {3 \, b^{2} x^{2}}{c^{3}}\right )} \log \left (-\frac {c x^{2} + 1}{c x^{2} - 1}\right ) + \frac {a b x^{2}}{4 \, c^{3}} - \frac {{\left (3 \, a b - 4 \, b^{2}\right )} \log \left (c x^{2} + 1\right )}{24 \, c^{4}} + \frac {{\left (3 \, a b + 4 \, b^{2}\right )} \log \left (c x^{2} - 1\right )}{24 \, c^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F(-2)] time = 180.00, size = 0, normalized size = 0.00 \[ \int x^{7} \left (a +b \arctanh \left (c \,x^{2}\right )\right )^{2}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.33, size = 217, normalized size = 1.74 \[ \frac {1}{8} \, b^{2} x^{8} \operatorname {artanh}\left (c x^{2}\right )^{2} + \frac {1}{8} \, a^{2} x^{8} + \frac {1}{24} \, {\left (6 \, x^{8} \operatorname {artanh}\left (c x^{2}\right ) + c {\left (\frac {2 \, {\left (c^{2} x^{6} + 3 \, x^{2}\right )}}{c^{4}} - \frac {3 \, \log \left (c x^{2} + 1\right )}{c^{5}} + \frac {3 \, \log \left (c x^{2} - 1\right )}{c^{5}}\right )}\right )} a b + \frac {1}{96} \, {\left (4 \, c {\left (\frac {2 \, {\left (c^{2} x^{6} + 3 \, x^{2}\right )}}{c^{4}} - \frac {3 \, \log \left (c x^{2} + 1\right )}{c^{5}} + \frac {3 \, \log \left (c x^{2} - 1\right )}{c^{5}}\right )} \operatorname {artanh}\left (c x^{2}\right ) + \frac {4 \, c^{2} x^{4} - 2 \, {\left (3 \, \log \left (c x^{2} - 1\right ) - 8\right )} \log \left (c x^{2} + 1\right ) + 3 \, \log \left (c x^{2} + 1\right )^{2} + 3 \, \log \left (c x^{2} - 1\right )^{2} + 16 \, \log \left (c x^{2} - 1\right )}{c^{4}}\right )} b^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.73, size = 335, normalized size = 2.68 \[ \frac {a^2\,x^8}{8}+\frac {b^2\,\ln \left (c\,x^2-1\right )}{6\,c^4}+\frac {b^2\,\ln \left (c\,x^2+1\right )}{6\,c^4}-\frac {b^2\,{\ln \left (c\,x^2+1\right )}^2}{32\,c^4}-\frac {b^2\,{\ln \left (1-c\,x^2\right )}^2}{32\,c^4}+\frac {b^2\,x^4}{24\,c^2}+\frac {b^2\,x^8\,{\ln \left (c\,x^2+1\right )}^2}{32}+\frac {b^2\,x^8\,{\ln \left (1-c\,x^2\right )}^2}{32}+\frac {b^2\,x^2\,\ln \left (c\,x^2+1\right )}{8\,c^3}-\frac {b^2\,x^2\,\ln \left (1-c\,x^2\right )}{8\,c^3}+\frac {b^2\,x^6\,\ln \left (c\,x^2+1\right )}{24\,c}-\frac {b^2\,x^6\,\ln \left (1-c\,x^2\right )}{24\,c}+\frac {a\,b\,\ln \left (c\,x^2-1\right )}{8\,c^4}-\frac {a\,b\,\ln \left (c\,x^2+1\right )}{8\,c^4}+\frac {a\,b\,x^8\,\ln \left (c\,x^2+1\right )}{8}-\frac {a\,b\,x^8\,\ln \left (1-c\,x^2\right )}{8}+\frac {b^2\,\ln \left (c\,x^2+1\right )\,\ln \left (1-c\,x^2\right )}{16\,c^4}+\frac {a\,b\,x^2}{4\,c^3}+\frac {a\,b\,x^6}{12\,c}-\frac {b^2\,x^8\,\ln \left (c\,x^2+1\right )\,\ln \left (1-c\,x^2\right )}{16} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 23.15, size = 206, normalized size = 1.65 \[ \begin {cases} \frac {a^{2} x^{8}}{8} + \frac {a b x^{8} \operatorname {atanh}{\left (c x^{2} \right )}}{4} + \frac {a b x^{6}}{12 c} + \frac {a b x^{2}}{4 c^{3}} - \frac {a b \operatorname {atanh}{\left (c x^{2} \right )}}{4 c^{4}} + \frac {b^{2} x^{8} \operatorname {atanh}^{2}{\left (c x^{2} \right )}}{8} + \frac {b^{2} x^{6} \operatorname {atanh}{\left (c x^{2} \right )}}{12 c} + \frac {b^{2} x^{4}}{24 c^{2}} + \frac {b^{2} x^{2} \operatorname {atanh}{\left (c x^{2} \right )}}{4 c^{3}} + \frac {b^{2} \log {\left (x - i \sqrt {\frac {1}{c}} \right )}}{3 c^{4}} + \frac {b^{2} \log {\left (x + i \sqrt {\frac {1}{c}} \right )}}{3 c^{4}} - \frac {b^{2} \operatorname {atanh}^{2}{\left (c x^{2} \right )}}{8 c^{4}} - \frac {b^{2} \operatorname {atanh}{\left (c x^{2} \right )}}{3 c^{4}} & \text {for}\: c \neq 0 \\\frac {a^{2} x^{8}}{8} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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